![]() The first method involves using the equation W = F*d*cos(Theta) There are two methods of solving this problem. Determine the work done upon the cart and the subsequent potential energy change of the cart. A force of 20.8 N is applied parallel to the incline to lift a 3.00-kg loaded cart to a height of 0.450 m along an incline which is 0.636-m long. A student applies a force to a cart to pull it up an inclined plane at constant speed during a physics lab. Substituting these values into the above equation yields W = F*d*cos(Theta) = (24.5 N)*(6 m)*cos(0) = ~150 J (147 J)Ģ7. In this case, the d=6.0 m the F=24.5 N (it takes 24.5 N of force to lift a 2.5-kg object that's the weight of the object), and the angle between F and d (Theta) is 0 degrees. The work done upon an object is found with the equation W = F*d*cos(Theta) Approximate the work required lift a 2.5-kg object to a height of 6.0 meters. Part B: Straightforward Computational ProblemsĢ6. The Review Session » Work and Energy Packet » Answers Q#26-36 Work and Energy Review ![]()
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